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Dempster-shafer and reasoning about sets

emiruz.com

22 points by usgroup a month ago · 8 comments

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esafak a month ago

DS theory has never been popular. Even Bayesianism (cf. "Bayesian nonparametrics" two decades ago) took a back seat after LLMs came out. DS theory, with its greater computational complexity, is therefore even less attractive.

  • js8 a month ago

    Yes and we are IMHO worse off, without a proper theory of reasoning under uncertainty, it's difficult to understand what LLMs are doing (or even hard to define what they should be doing).

    I agree that DS is computationally prohibitive, but another way out (aside from probability, which I don't like either) is with various systems of fuzzy logic (or you can just go with the most expressive one under the lovely name \L\Pi 1/2).

    (BTW I am also exploring approach to uncertainty based on untyped lambda calculus, where each term is interpreted as a kind of "model of the world". Uncertainty degree is given by whether the term has a normal form or not. If it has not, then it is certain, while if it has a normal form, it means that additional assumptions/arguments need to be supplied to specify the model further.)

  • usgroupOP a month ago

    I think that's overly reductivist. In the general case DS operates on up to 2^M sets where M is the cardinality of the hypothesis space: worst case scenario. That's not true if hypotheses are hierarchical, or if evidence is frequently about the same set, or there just isn't enough evidence to fuse to get to 2^M.

    In the worst case scenario there are efficient approximation methods which can be used.

mturmon a month ago

This reminds me of `PrSAT`, a satisfier for probabilistic statements. ("Does a distribution exist that satisfies the following constraints?").

See: https://fitelson.org/PrSAT/, and the linked paper: https://fitelson.org/pm.pdf

The paper starts off slow, but have patience to read up to section 4, Applications, which is kind of surprising.

  • usgroupOP a month ago

    Thanks for this reference; I found this paper interesting, but it is a satisfiability solver. Inherently it cannot quantify the probability of a subset of events, but it can find a probability assignment given a set of constraints. I.e. prove possibility. More usefully it can show that no such assignment is possible.

csense a month ago

I don't understand what the notation means.

For example when the author says:

P(Q ⊆ X | ∀ x ∈ Q (x = 1))

This is equivalent to P(Q ⊆ X | Q = {1}), which further simplifies to P(1∈X).

This seems to be a type error (isn't X supposed to be a set of binary variables?), and also an awfully cumbersome way to write P(1∈X).

Anyone have some idea what the article is trying to say?

  • usgroupOP a month ago

    It's a typo. Its supposed to be a comma not a pipe, and read P(Q ⊆ X , ∀ x ∈ Q (x = 1)). I.e. Q is some subset of X and for all x in Q, x=1.

gneray a month ago

What a dempster fire

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