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Record-breaking neutrino is most energetic ever detected

nature.com

229 points by lnauta 10 months ago · 136 comments

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thamer 10 months ago

It took a few tries, but I got Wolfram Alpha to compute its velocity compared to the speed of light[1].

I started with:

    sqrt(1-((1/(1+120 PeV / (neutrino mass * c^2)))^2))
but it simply said "data not available". So I changed:

    120 PeV to 120e15 * 1.602176634e-19 kg m^2 s^-2
    neutrino mass to 1.25e-37kg
    speed of light to 299792458 m/s
and finally it gave a numeric result:

    0.999999999999999999999999999999999999829277971
(that's 36 nines in a row). Pasting it in Google says the value is "1", which is… not far off.

If you want details about the way this is calculated, I dug up the formula from an article I'd written about particle velocities in the LHC, back in 2008[2]. For comparison, their 7 TeV protons were going at 0.999999991 × c.

[1] https://www.wolframalpha.com/input?i=sqrt%281-%28%281%2F%281...

[2] https://log.kv.io/post/2008/09/12/lhc-how-fast-do-these-prot...

  • davrosthedalek 10 months ago

    We don't know the neutrino's masses, so this is a lower limit for v (since the mass you used is an upper limit)

  • dr_dshiv 10 months ago

    That’s fast! But for how much energy? For comparison, the total energy from this one particle (0.0192 joules) is equivalent to keeping a 50 mW LED lit for a third of a second.

  • wd776g5 10 months ago

    I can see it came from your source but why is the neutrino mass specified in kg instead of g? why not 1.25e-34g?

    • thamer 10 months ago

      The kilogram is the base unit of mass in the International System of Units (SI): https://en.wikipedia.org/wiki/SI_base_unit

      Time is in seconds, length in meters, temperature in kelvin, etc. A unit of energy like a joule is then defined using these base units, so 1 joule is 1⋅kg⋅m^2⋅s^-2.

      • skissane 10 months ago

        > The kilogram is the base unit of mass in the International System of Units (SI)

        Arguably, an ugly wart, but one we are stuck with for historical reasons. The base units of the original metric system (metre and gram) were poorly proportioned for practical use, resulting in the two main scientific/engineering systems of metric units both choosing to prefix one base unit - the centimetre-gram-second (cgs) system chose to prefix the metre, the metre-kilogram-second (mks) system chose to prefix the gram, and eventually mks won out over cgs and evolved into SI.

        Whatever warts SI has, they are nothing compared to the chaos of the Imperial/customary system

        • myrmidon 10 months ago

          > The base units of the original metric system (metre and gram) were poorly proportioned for practical use

          What is the dealbreaker here though? Because we have plenty of "poorly proportioned" SI units anyway; e.g. it would be much more practical to have megapascal, microfarad and megajoule as base units from an engineering pov (particle physicists might disagree;).

          • skissane 10 months ago

            Pascal, farad, joule aren't base units, they are derived units.

            Ideally, the base units should be prefixless. Except for kilogram, they all are.

            Imagine a system exactly the same as SI, except instead of the kilogram, it had the kram, where 1 kram = 1 kilogram... then the gram would be the millikram, the milligram would become microkram, the microgram would become the nanokram, etc... if you were starting from scratch, without any historical baggage, wouldn't such a system be superior? But of course, we aren't starting without historical baggage – almost everybody knows what a kilogram is, kram is a word I just now made up.

            I think some derived units being "poorly proportioned" is inevitable given the physics we have.

            • myrmidon 10 months ago

              I understand what you mean-- I was just curious about why we could not just stick with gram-meter-second (since we have a bunch of "poorly proportioned" derived units anyway)...

              • adrian_b 10 months ago

                Using the gram would not have removed the prefixes from all commonly used units.

                In the beginning, the liter was a much more frequently used unit of volume than the cubic meter.

                A liter was defined as the volume of a kilogram of water. In a system were the gram was the unit of mass, the corresponding unit of volume was the milliliter.

                Which of the gram and the kilogram or which of the centimeter and meter were chosen as the units of mass and length did not matter much for mechanical units, in the way they were used in practice in the 19th century.

                A definite choice of the base units has become important only after a bunch of new physical quantities have been defined for use in the theories of electricity, magnetism, heat and light, in the second half of the 19th century. When dealing with so many different physical quantities, not using unique base units would have caused too much confusion. While this necessity has been recognized, for many years 2 different choices for the base units were widespread, that based on meter-kilogram (used mostly by engineers) and that based on centimeter-gram (used mostly by theoreticians). Meter and kilogram were more typical for the sizes of practical machines, while centimeter and gram were more typical for the sizes of laboratory experiments.

          • Sharlin 10 months ago

            If the base unit were gram, megapascals would be gigapascals, microfarads would be nanofarads, and megajoules gigajoules. Similarly a watt would be what's now a milliwatt and most "everyday" powers (except in electronics) would be kilowatts or megawatts.

    • l33tman 10 months ago

      In particle physics you just use GeV (with varying powers) for most parameters :)

ziddoap 10 months ago

Ars Technica has an article, as well, with some additional context/explanation.

https://arstechnica.com/science/2025/02/most-energetic-neutr...

And an interesting, somewhat related, video from PBS Space Time exploring how supernovas act as particle accelerators (but don't quite explain particles like this one or the 'Oh My God' particle):

https://www.youtube.com/watch?v=2sSNWIJbV3Q

  • dr_dshiv 10 months ago

    Neutrinos “interact with regular matter so rarely that it's estimated you'd need about a light-year of lead to completely block a bright source of them. Every one of us has tens of trillions of neutrinos passing through us every second, but fewer than five of them actually interact with the matter in our bodies in our entire lifetimes.”

    They have 1/500,000 the mass of electrons. They interact only through the super short range weak force (and gravity). Nearly 5% of fission energy is expressed in neutrinos.

    And, they may be their own antiparticles, meaning they can potentially annihilate each other.

    Wild that these things can carry so much energy!

    • ricksunny 10 months ago

      >Every one of us has tens of trillions of neutrinos passing through us every second, but fewer than five of them actually interact with the matter in our bodies in our entire lifetimes.”

      Oh, but those five...

    • steveoscaro 10 months ago

      These rare interactions with matter are also a cause of concern in voting machines, right? Or at least it was a concern at one point. A random bit being flipped or something.

      • tasty_freeze 10 months ago

        It is mostly a problem of DRAM memory cells, though theoretically with enough energy it could flip SRAM cells to or override the driver of a given wire. It is not specific to voting machines.

        But the main source is from cosmic rays and local radiation sources in the ceramic packaging and/or decaying elements in the metal frame/leads/solder.

      • dtgriscom 10 months ago

        Other types of particles interact much more frequently. But yes: bits do get flipped (even with ECC memory).

    • irchans 10 months ago

      Interesting "fact" - The total amount of lead in the universe is a somewhat less than a cubic light year.

      • sfn42 10 months ago

        How could we possibly estimate that if we don't even know the size of the universe?

cylinder714 10 months ago

The article references the "Oh-My-God particle, the most energetic particle yet encountered. Here's the late John Walker's excellent piece on that:

https://fourmilab.ch/documents/OhMyGodParticle/

jihadjihad 10 months ago

The Nature paper itself can be found here [0], for those curious. Was just published today.

0: https://www.nature.com/articles/s41586-024-08543-1

antognini 10 months ago

For context, 120 PeV is about 10% the kinetic energy of a ping pong ball during typical play.

  • s1110 10 months ago

    Does this count as "Americans will measure with anything but the metric system"?

  • lnautaOP 10 months ago

    One of the lead researchers in KM3NeT mentioned that the particle was emitting 2 horse power in light during detector transit. A typical body builder expends about 1 horse power while performing, so its 2 body builders in a single particle.

    • A_D_E_P_T 10 months ago

      > typical body builder expends about 1 horse power while performing

      Close, but ackshually...

      Bodybuilders just oil up and pose in beauty pageants.

      1 horsepower is basically one 250-pound bench press in one second. (550 foot pounds of work; the aforementioned bench press assumes a 2.2-foot stroke length.)

      Most bodybuilders and serious weight lifters can do that, but they can't keep it up for long.

    • zozbot234 10 months ago

      Fun fact, a typical horse exerts about 1 horse power of usable work while performing. That's so weird, I'm sure almost no one would've been able to guess that - but it's true.

      (To be clear, that's sustained effort over time, not just momentary. Athletically trained humans can do about 1 HP of peak momentary effort, and around 0.3 HP if sustained over time.)

      • mikepurvis 10 months ago

        And a horse can do quite a bit more in peak as well— 1 HP is definitely meant to be the long term continuous output of a typical horse under load, especially a consistent load such as turning a millstone.

      • loeg 10 months ago

        That's an all-day number. Peak HP/horse is somewhere in the 6-15 range.

      • somat 10 months ago

        The funny thing is that a typical horse probably has closer to 2 or 3 horsepower and a big chonkin draft horse up to 4 or 5 times.

        James Watt just picked the smallest possible value of horse when defining the unit so he could sell more steam engines.

        https://www.youtube.com/watch?v=7qxTKtlvaVE (donut, How Much Horsepower is a Horse?)

      • wiredfool 10 months ago

        Track cyclists (sprinters, world class) do 2KW+ peak for a few seconds at a time. That's potentially ~3HP. (and while doing so, average more than 70kph over a 200m distance)

    • 01HNNWZ0MV43FF 10 months ago

      It must have been a very short amount of time. 2 HP is 1,500 watts, probably more light than all lightbulbs in my house combined.

    • whyenot 10 months ago

      So, 2,000 milliSchwarzeneggers if we use SI units?

      • gattr 10 months ago

        Yes, but please observe SI rules [1]: it's millischwarzeneggers.

        > This means that they should be typeset in the same character set as other common nouns (e.g. Latin alphabet in English, Cyrillic script in Russian, etc.), following the usual grammatical and orthographical rules of the context language. For example, in English and French, even when the unit is named after a person and its symbol begins with a capital letter, the unit name in running text should start with a lowercase letter (e.g., newton, hertz, pascal) and is capitalised only at the beginning of a sentence and in headings and publication titles.

        [1] https://en.wikipedia.org/wiki/International_System_of_Units#...

    • m3kw9 10 months ago

      Can we harvest that energy?

      • __MatrixMan__ 10 months ago

        Not for that particular neutrino, it's gone. But yes, my home (and yours) is being heated by neutrino power as we speak. It's not a significant enough amount of energy to make a dent in the utility bill however.

        • Sharlin 10 months ago

          Most inefficient thermal power plant possible: utilize the difference in neutrino flux between the hemisphere that's open to space vs. the hemisphere where Earth is in the way.

          But now I'm wondering what percentage of the useful thermal power in a nuclear power plant is produced by the neutrinos created in the reactions (the infinitesimally small fraction that happen to interact with the matter within the reactor, that is).

          • __MatrixMan__ 10 months ago

            On the contrary, it would have to be efficient indeed to do anything useful underneath all of the shielding that we'd need to keep those baser forms of radiation at bay. Gamma rays: yuck.

      • AnimalMuppet 10 months ago

        This particle spread this energy through a volume of seawater a few km deep in the Mediterranean. It's going to raise the temperature of that volume a few billionths of a degree, if that. So, no, we can't.

        • the_arun 10 months ago

          What if our existing solar panels are optimized to detect these? Then will it improve the quality of solar panels to capture more energy from sunlight as well? Sorry, I'm no expert in this - asking more of a curiosity.

          • tsimionescu 10 months ago

            There's nothing to optimize here, neutrinos just interact very very weakly with anything else because they don't carry charge (so no electrical interactions), don't carry color charge (so no nuclear interactions), don't carry weak charge (so no weak force interactions) and have tiny tiny masses, but they are still bosons (so don't act as field carriers like photons do, they're just regular matter). Their low chance of interacting with matter is a fundamental property of them, there's nothing you can do about it through technology, just like you can't create heavier electrons or weaker quarks.

            • gus_massa 10 months ago

              > don't carry weak charge (so no weak force interactions)

              Left neutrino have weak hypercharge, so they are produce by weak interactions and are detected using the weak interaction. And also gravity.

              Right neutrinos (if they exist) have no weak hypercharge so they only interact by gravity.

          • tadfisher 10 months ago

            Neutrinos interact extremely weakly with ordinary matter, which is why the detectors are typically huge volumes of water. Even then, the neutrinos interact with the purpose-built detectors on the order of one in a trillion. A neutrino power generator is not a feasible thing to build.

          • ars 10 months ago

            It's an enormous amount of energy packed into a single tiny particle.

            But it's still just a single tiny particle, so it's not a lot of total energy.

            It's like how you can lift a heavy weight for a second, but that's all you can do. You would need to be able to lift it for hours to be useful as a replacement for a crane. Same idea: Intensity vs total work.

          • mr_toad 10 months ago

            If we had the ability to detect neutrinos in such a small volume as a solar panel they’d be immensely valuable for communication - we’d be able to beam signals directly through the Earth, or through deep water.

          • __MatrixMan__ 10 months ago

            It might improve the quality of neutrino astronomy to have the world's solar panels also be neutrino detectors.

    • rq1 10 months ago

      Particle on steroids.

  • jihadjihad 10 months ago

    Right, and it is this amount of energy in a single particle. A ping-pong ball is comprised of who-knows-how-many billions of particles, so the energy of any one particle is a fraction of the whole.

  • GuB-42 10 months ago

    Now, what will happen if you get hit by a ping-pong ball mass of 120 PeV neutrinos? 120 PeV is about 2e-16 grams, so a ping-pong ball will have about 1e16 of them.

    From nothing, to detectable, to lethal, to big boom?

    My intuition would be "detectable" but I don't know enough to do the maths.

    And by the way, I am using the mass-energy, not proper mass, because the question is crazy enough not to even consider what would be the mass of a neutrino.

    • antognini 10 months ago

      The mean free path of neutrinos through lead is around one light-year. So, taking the thickness of the body to be 1/2 a meter, you would expect the probability of any individual neutrino to interact with the body to be ~5 x 10^-17. So you'd ballpark have around a 20--40% chance that a single neutrino interacts with your body. It would probably cause a localized radiation burn. Detectable, but probably not lethal unless you got really unlucky with where it hit you.

      • pfdietz 10 months ago

        The mean free path of much lower energy neutrinos in lead is about a light year.

        The MFP of a 120 PeV neutrino in lead would be something like 10 kilometers, I think.

        • cozzyd 10 months ago

          More like 100 km I'd think but yeah, the neutrino nucleon cross section gets much bigger at high energies

    • mppm 10 months ago

      > big boom

      The probability of interaction of neutrinos with matter increases with the energy. I've asked o1 to estimate the mean free path of a 120 PeV neutrino in water and it came up with 1000km. So let's say, conservatively, that 10^-7 of the total energy gets deposited in your body when the beam goes through. The mass equivalent of a ping pong ball is about 2.5x10^14 J, which gives us 2.5x10^7 J total, or about 6kg TNT equivalent. This is only an order-of-magnitude estimate, but it would definitely not be healthy.

    • queuebert 10 months ago

      Total energy of impact would be 120 PeV x 10^16 = 120 x 10^31 eV = ~60 kilotons TNT, or 4 Hiroshimas.

      So BIG boom.

      Since the velocity is so close to the speed of light, you can think of this like the energy released by annihilating a ping pong ball made of antimatter.

      Edit: Commenter asked what would happen if they "hit", so I'm assuming a hypothetical 100% collision. But yes to stop 1/e of a neutrino beam with normal matter, you'd need a light year of lead.

    • dahousecat 10 months ago

      Sounds like a great topic for an xkcd video

  • scotty79 10 months ago

    There's interesting "end of life" scenario. Nearby supernova exploding and sending so many high energetic neutrinos that even with their rare interactions they could mess up all chemistry that biology uses. And you wouldn't be able to shelter from it since the whole planet is basically transparent to them.

  • jl6 10 months ago

    So, according to basic Ant-Man theory, if I were hit by one of these, it should be like getting all that (10% of a) ping pong ball energy concentrated in a tiny spot, causing me to fly backwards across the room?

    • parineum 10 months ago

      Isn't Ant-Man logic that he still has the same mass when he shrinks and, as such, can generate the same force?

      Unless you get thrown back by ping pong balls normally, I think you'd be fine.

      • class700 10 months ago

        And yet when he grows he still has enough strength to punch a leviathan out of the sky. I'm not sure there's such thing as ant man logic - It doesn't seem like it should result in strength both ways.

        • voidUpdate 10 months ago

          His weight also changes with size, or doesnt, depending on what would be more convenient for the current scene

    • BobaFloutist 10 months ago

      I would expect it to be more likely to punch through skin than to actually propel you.

      But also neutrinos don't typically collide with things very easily, they're more likely to pass through you without you ever knowing.

      • Aachen 10 months ago

        I was thinking the same though. It doesn't interact often, but if it randomly does annihilate with another particle in your body, at such a small scale (subatomic) that force/pressure just destroys anything in its path no? Like a paint flake hitting a space ship. Or is it more like "light" (since they're iirc their own antiparticle), which is then absorbed by surrounding matter and turns into heat?

        In the wrong spot, this sounds to me like it kills you?

        Nothing to be afraid of, of course, for the reason you mentioned. Just wondering, xkcd "what if" style

      • moffkalast 10 months ago

        Yeah there's no way it would be able to grip onto anything, probably more like the Bugorski case, where he stuck his head into a particle accelerator and a proton beam went right through his head.

  • xarope 10 months ago

    the way I play ping pong (holding the paddle like an ice cream stick)? or the way a professional ping pong player plays (which probably means they are serving aces on me all day)?

  • ahazred8ta 10 months ago

    120 PeV is 0.020 of a Joule, or 20 milliwatt-seconds.

ziofill 10 months ago

It's mentioned in the article that the highest energy ever recorded for a single particle was 320,000 PeV which is about 50 joules, i.e. the energy of a golf ball at 100 mph @_@

  • queuebert 10 months ago

    That was a cosmic ray proton, which has probably 10 billion times the mass of a neutrino and interacts much more strongly with normal matter. A nuclear juggernaut vs a ninja by comparison.

    • cozzyd 10 months ago

      Most likely a heavier nucleus than a proton too

      • adaml_623 10 months ago

        Would a nucleus composed of multiple nucleons stay stuck together with that much energy? If it's zipping along and not interacting with the anything then sure but how did it get that much energy in the first place?

        • cozzyd 10 months ago

          Yes, while there is a large amount of uncertainty, it is believed they the majority of the highest energy cosmic rays are nuclei of elements like iron. For people like me, in the business of finding high energy neutrinos (I'm not involved in km3net, btw), that's a bad thing since that means the highest energy cosmic rays convert less efficiently into neutrinos when interacting with the cosmic microwave background.

          How they got so much energy in the first place is kind of an open question. Generally it involves magnetic fields and shock fronts, getting a little kick each time (but yes, you also have to avoid disintegrating the nucleus in the acceleration environment!)

insane_dreamer 10 months ago

also reported in the NYT: https://www.nytimes.com/2025/02/12/science/astrophysics-univ...

dooglius 10 months ago

It looks like they detected a muon and are inferring a neutrino from the fact it went through a lot of solid. Couldn't it be any other weakly-interacting particle though?

  • Sniffnoy 10 months ago

    How? Quarks can't change into leptons. Charged leptons can't change directly into other charged leptons. And neither charged leptons nor hadrons are going to pass through such a quantity of matter, as you say. I mean I assume other cases are technically possible but they don't seem very likely...

  • AnimalMuppet 10 months ago

    Nit: As I read the article, they aren't sure that it went through any solid. Went through a lot of seawater, though. And your argument still applies.

  • cozzyd 10 months ago

    It could be beyond the standard model physics but no other standard model particle could work other than a neutrino.

  • nxpnsv 10 months ago

    Nothing else that we know of would create a muon of that energy deep inside bedrock.

pfdietz 10 months ago

If I understand correctly, the interaction length of such an energetic neutrino in rock is only in the tens of kilometers.

neals 10 months ago

Anybody here able to tell me what it means? Where do neutrinos get their energy from? Is there a limit? Will this make my phone smaller? My microwave quicker?

bookofjoe 10 months ago

>Observation of an ultra-high-energy cosmic neutrino with KM3NeT

https://www.nature.com/articles/s41586-024-08543-1

ge96 10 months ago

What's faster than satellite communication? Neutrinos baby

Not even sure if that's worth doing, either create/emit or use encode data into them as they fly by to be received by someone else

Edit: that's cool people have tried though

octocop 10 months ago

Why do they place the receiver in a large body of water, like the Mediterranean?

  • tjpnz 10 months ago

    Neutrino interactions with nuclei of water produce charged particles which move faster than the speed of light in water (but slower than through a vacuum tube) creating a cone of light known as Cherenkov radiation, which is the optical equivalent to a sonic boom. This is projected onto a ring around the detector.

    Doesn't need to be submerged in a body of water as large as this. The Super-Kamiokande[0] detector for instance is located in a body of water inside a mountain.

    0: https://en.m.wikipedia.org/wiki/Super-Kamiokande

yapyap 10 months ago

bit of a redundant title

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