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Susctl CVE-2024-54507: A particularly 'sus' sysctl in the XNU kernel

jprx.io

148 points by jprx a year ago · 46 comments

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kwitaszczyk a year ago

This is a nice and easy to understand example of a memory-safety bug that CHERI [1] prevents (among other classes of vulnerabilities). Given that the SYSCTL_PROC() macro installs a pointer to an uint16_t value in the oid_arg1 field, a CHERI pure-capability kernel would construct a capability with bounds set to sizeof(uint16_t) and later the dereference of (int *)oidp->oid_arg1 in sysctl_udp_log_port() would trigger a capability bounds violation.

`sysctl -a` would simply crash on CHERI allowing a developer to catch this without KASAN being involved.

[1] http://cheri-cpu.org

nixpulvis a year ago

Seems like something to be integration tested in the future. Honestly surprised this slipped through.

  • 0x457 a year ago

    I saw that types are different, but I was thinking "must be some weird C thing that I don't know about"

  • StressedDev a year ago

    I am not surprised. First, it's a subtle bug. Second, in C/C++. a lot of times you get unlucky when reading uninitialized memory. Basically, the bug does not occur when you test the code on your machine or when you run the automated tests.

    Another problem is writing good automated tests is hard and often skipped. Lots of software engineering teams talk about the wonders of automated tests. Unfortunately, many automated tests are not very good and either do not ensure the major functionality works or just do not test some of the code. There are also limits to how much time a software engineer has to test. No one can test everything.

    Basically, I am not surprised developers make mistakes and I am not surprised the tests either did not catch this mistake or even did not exist. Software is very hard and software engineers are far from perfect.

nxobject a year ago

Did you get a bounty payout for this? I got the impression that Apple wasn't particularly on the ball with those.

  • ChocolateGod a year ago

    Is it even exploitable in the real world?

    Correct me if I'm wrong but you get 2 bytes of kernel data (potentially blank padding) and the same two bytes each time?

    • bean-weevil a year ago

      If the linker puts a pointer there, this would let you leak part of the pointer which could let you bypass kaslr. Not too likely for that to occur. If I were submitting this bug I would feel complete if they bought me a sandwich.

      • axoltl a year ago

        The bottom 2 bytes of a pointer contain two bits of the slide, assuming it's even a pointer into the kernelcache itself.

        I'd take half a sandwich.

        • the-rc a year ago

          Little endianness considered harmful

        • bean-weevil a year ago

          Yeah, you could probably contrive a situation where you get more interesting information (page numbers maybe?), but it definitely doesn't seem likely to me-

    • buzzergfxkjkl a year ago

      Good to find the bug regardless! I appreciated the succinct and not overly dramatic write-up. I don't think anything significant was claimed other than the fact that it is a kernel bug (which is significant in itself don't get me wrong).

    • duskwuff a year ago

      You are correct. It's clearly a bug, but the impact in shipping kernels appears to be limited to "leaking" some non-sensitive data.

inetknght a year ago

    -   int new_value = *(int *)oidp->oid_arg1;
    +   int new_value = *(uint16_t *)oidp->oid_arg1;
Why not just have `uint16_t new_value = ...`?

Ahh, because `new_value` is being given to `sysctl_handle_int(..., &new_value, ...);` which of course expects an `int`. So then it begs the question: if the value is really a `uint16_t`, then why is it being handled through a plain `int`? It smells like there could easily be tons of other memory-safety and/or type confusion problems endemic to the sysctl API.

  • aritashion a year ago

    > So then it begs the question: if the value is really a `uint16_t`, then why is it being handled through a plain `int`?

    I don't think it begs the question, but it does raise one!

  • kccqzy a year ago

    Well there's the so-called usual arithmetic conversions that will basically convert every uint16_t to an unsigned int. The C and C++ languages do a silent conversion on your back anyways so you might as well make it explicit.

    • loeg a year ago

      Usually promotions are to signed int, not unsigned. (With some exceptions. But every uint16_t value can fit in int.)

      • Filligree a year ago

        Unless int is 16-bit. Code like this is potentially UB; you should use int32_t as the target.

        • kevin_thibedeau a year ago

          You should use long, and don't ever assume it's exactly 32-bits. The fixed size types are often an overused crutch that hampers future portability.

        • loeg a year ago

          There are no mainstream 16-bit int platforms. It's fine to know what you target.

          The promotions that are really surprising are from uint64_t bitfields to int (because it's based on value representability).

            struct {
              uint64_t a : 33,
                       b : 15;
            } s;
            // s.b gets "promoted" to int, s.a does not
    • inetknght a year ago

      A well-configured C++ compiler will error-out on such a silent conversion.

soheil a year ago

Leaking two random bytes and in some cases just padding bytes to user space is not the end of the world and I don't get why there are so many negative comments blaming Apple for not handing out a handsome bounty for this bug.

  • StressedDev a year ago

    It's still a security bug. Often, multiple bugs like this are chained together to create one very nasty exploit. I agree that this bug probably does not deserve a massive payout, but I think $3,000-5,000$ is appropriate.

yapyap a year ago

I appreciate the among us.

jfasi a year ago

Interestingly, ChatGPT correctly points out this exact issue:

https://chatgpt.com/share/6793a2d1-5f84-8006-8e78-16be4d4908...

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