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Blake 32

pouet.net

81 points by knoke 5 years ago · 22 comments

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jeffgreco 5 years ago

YouTube link for those of us without DOS handy: https://youtu.be/kM2i2s4ItiA

_yoqn 5 years ago

This is a surprisingly delightful niche of computer art I've never seen before. Poke around the homepage some, you'll find some very creative ones.

bottled_poe 5 years ago

What exactly are we looking at here?

  • mhh__ 5 years ago

        mov al,13h   ; 2
        int 10h     ; 2
        frameloop:
         les ax,[bx]  ;  2 
         mov ah,0xcc  ;  2 
         mul di   ;  2 
         mov al,16  ;  2
         fractalloop:
          ja snobby ; 2
          inc ax  ; 1
          snobby:
          adc dl,[fs:0x46C] ; 5 (f&^k this shit!)
          sbb dh,dl       ; 2 
          ror dl,cl ; 2 
          adc dl,dh       ; 2 
         jno fractalloop  ; 2
         stosb   ; 1
        jmp frameloop         ; 2
        nop     ; bonus, because 32 bytes was too much free space for me.
    • raverbashing 5 years ago

      Nice, I'm old enough to know what the 2 first lines do (get off my lawn etc...)

      For the rest it would take a while to understand the math and I'm not even sure where 0xa0000 would come from

      • pdw 5 years ago

        That confused me as well. The Mode 13h graphics framebuffer is at address A000:0000. How does this program get that value?

        The key is the LES AX,[BX] opcode. BX is initialized to 0 by DOS, and the "Set video mode" BIOS call preserves BX's value. So the LES opcode sets ES:AX by reading a dword from DS:0.

        What's there? A COM file is a single-segment program, so DS equals CS, and the code segment starts with the Program Segment Prefix. (The actual code is loaded at offset 100h.) So it loads the first two words of the PSP. What are those?

        The first word is an "INT 20h" instruction, 20CDh, for compatibility with CP/M.

        The second word is the segment number of the end of the memory allocated for the program. But DOS always allocates all memory to COM programs, so this will be 0x9FFF (assuming you have a full 640K conventional memory installed).

        So ES:AX is set to 9FFF:20CD. And with x86 segmented memory 9FFF:0010 equals A000:0000.

      • alfiedotwtf 5 years ago

        Ha!

        I’ve toyed through out the years that if I ever got a tattoo, it would be:

        mov ax, 13h;

        int 10h

    • ur-whale 5 years ago

      Thanks for the concise answer :)

  • alasdair_ 5 years ago

    A contest-winning 32 byte computer program that displays amazing visuals. Part of the “demo” scene.

    • pixelpoet 5 years ago

      Writing "demo" scene is like writing "web" site: come on, this has been around since the 80s. We literally have a post on the front page about demoscene being a recognised cultural heritage now.

  • simlevesque 5 years ago

    UNESCO's cultural heritage.

  • itisit 5 years ago

    As alasdair_ mentioned, this is some impressive demoscene stuff. Which, if I may take the liberty, is all about maximal creative output (subjective, I know) with minimal data footprint. In case you missed in original post, a video of the demo:

    https://youtu.be/kM2i2s4ItiA

    32 bytes!

HHad3 5 years ago

And its last byte is a NOP, quite a flex :-).

slim 5 years ago

My brain could not admit it was 32b and insisted on parsing it as 32kb anytime it was displayed. It's when I saw the demo, expected more, then go wtf!?...

ur-whale 5 years ago

Anyone care to comment on the name ?

  • bajsejohannes 5 years ago

    From the source:

    ; Inspired by "Auguries of Innocence", a poem by William Blake

    ;

    ; To see a World in a Grain of Sand

    ; And a Heaven in a Wild Flower

    ; Hold Infinity in the palm of your hand

    ; And Eternity in an hour

    And 32 is of course the size in bytes of the executable.

    • tech2 5 years ago

      Double-bonus, 32 is also the word count of poem plus title (sans author name).

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