Stuff you might didn't know about CoffeeScript
recodes.coI found the following example to be extremely confusing:
a = 10
b = 5 > a > 30
When I thought about it after seeing what it compiles to: var a, b;
a = 10;
b = (5 > a && a > 30);
I couldn't see how that statement could be true because a cannot be less than 5 while also be greater than 30.Range checking I would assume would be:
b = 5 < a > 30You are absolutely right!
The range check would be "`5` is less than `a` and `a` is less than `30`". Meaning that `a` is between 5 and 30.
It's fixed now. Thanks martin-adams!
Glad I could help. And also noticed that you fixed the error in my version as well - ha!